Monday, December 29, 2008

Project Euler and PowerShell - Problem 6

This was an easy one!
The sum of the squares of the first ten natural numbers is,

1^(2) + 2^(2) + ... + 10^(2) = 385

The square of the sum of the first ten natural numbers is,

(1 + 2 + ... + 10)^(2) = 55^(2) = 3025

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

$sumSquares = $squareSums = $difference = 0
for ($i=1;$i -le 100;$i++)
{
$sumSquares += [Math]::Pow($i,2)
$squareSums += $i
}
$difference = [math]::Pow($squareSums,2) - $sumSquares
$difference

No comments: